Electro Magnetic Induction And Alternating Currents Question 412
Question: In an AC circuit, the voltage applied is $ E=E_{0}\sin \omega t $ . The resulting current in the circuit is $ I=I_{0}\sin (\omega t-\pi /2) $ . The power consumption in the circuit is given by
Options:
A) $ P=0 $
B) $ P=\frac{E_{0}I_{0}}{2} $
C) $ P=\sqrt{2} $ $ E_{0}I_{0} $
D) $ P=\frac{E_{0}I_{0}}{\sqrt{2}} $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ P_{av}=E_{V}I_{V}\cos \phi $ Here $ \phi = $ phase difference $ =\frac{\pi }{2} $
$ \therefore P_{av}=0 $
BETA
