Electro Magnetic Induction And Alternating Currents Question 13
Question: A resistance of 300 W and an inductance of $ \frac{1}{\pi } $ henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is [Roorkee 1980]
Options:
A) $ {{\tan }^{-1}}\frac{4}{3} $
B) $ {{\tan }^{-1}}\frac{3}{4} $
C) $ {{\tan }^{-1}}\frac{3}{2} $
D) $ {{\tan }^{-1}}\frac{2}{5} $
Show Answer
Answer:
Correct Answer: A
Solution:
Phase angle $ \tan \varphi =\frac{\omega L}{R}=\frac{2\pi \times 200}{300}\times \frac{1}{\pi }=\frac{4}{3} $
$ \therefore ,\varphi ={{\tan }^{-1}}\frac{4}{3} $
BETA
