Electro Magnetic Induction And Alternating Currents Question 427
Question: A copper disc of radius 0.1 m is rotated about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of disc is [MH CET (Med) 2001]
Options:
A) $ \frac{\pi }{10}\ V $
B) $ \frac{2\pi }{10}\ V $
C) $ \pi \times {{10}^{-2}}V $
D) $ 2\pi \times {{10}^{-2}}V $
Show Answer
Answer:
Correct Answer: C
Solution:
$ e=\frac{1}{2}B\omega r^{2}=\frac{1}{2}\times 0.1\times 2\pi \times 10\times {{(0.1)}^{2}} $ $ =\pi \times {{10}^{-2}}V $
BETA
