Electro Magnetic Induction And Alternating Currents Question 431
Question: A coil of area 80 square cm and 50 turns is rotating with 2000 revolutions per minute about an axis perpendicular to a magnetic field of 0.05 Tesla. The maximum value of the e.m.f. developed in it is [MP PMT 1994]
Options:
A) $ 200\pi ,volt $
B) $ \frac{10\pi }{3}volt $
C) $ \frac{4\pi }{3},volt $
D) $ \frac{2}{3} $ volt
Show Answer
Answer:
Correct Answer: C
Solution:
$ e=NBA\omega ;\ \omega =2\pi f=2\pi \times \frac{2000}{60} $
$ \therefore \ e=50\times 0.05\times 80\times {{10}^{-4}}\times 2\pi \times \frac{2000}{60}=\frac{4\pi }{3} $
BETA
