Electro Magnetic Induction And Alternating Currents Question 454
Question: Fig shown below represents an area $ A=0.5m^{2} $ situated in a uniform magnetic field $ B=2.0weber/m^{2} $ and making an angle of $ 60{}^\circ $ with respect to magnetic field. The value of the magnetic flux through the area would be equal to
Options:
A) 2.0 weber
B) $ \sqrt{3}weber~~~ $
C) $ \sqrt{3}\text{/2 }weber $
D) 0.5 weber
Show Answer
Answer:
Correct Answer: D
Solution:
- $ \phi =BA\cos \theta =2.0\times 0.5\times \cos 60^{o} $ $ =\frac{2.0\times 0.5}{2}=0.5weber. $
BETA
