Electro Magnetic Induction And Alternating Currents Question 46
Question: In the non-resonant circuit, what will be the nature of the circuit for frequencies higher than the resonant frequency [RPET 1996]
Options:
A) Resistive (Please provide additional context for a proper evaluation)
B) Capacitive coupling
C) Inductive reasoning
D) None of the above
Show Answer
Answer:
Correct Answer: B
Solution:
In non resonant circuits impedance $ Z=\sqrt{R^{2}+{{( \omega L-\frac{1}{\omega C} )}^{2}}} $ , with rise in frequency Z increases i.e. current decreases so circuit behaves as inductive circuit.
BETA
