Electro Magnetic Induction And Alternating Currents Question 460
Question: A vertical ring of radius r and resistance R falls vertically. It is in contact with two vertical rails which are joined at the top. The rails are without friction and resistance. There is a horizontal uniform magnetic field of magnitude B perpendicular to the plane of the ring and -the rails. When the speed of the ring is v, the current in the top horizontal of the rail section is
Options:
0
B) $ \frac{2Brv}{R} $
C) $ \frac{4Brv}{R} $
D) $ \frac{8Brv}{R} $
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Answer:
Correct Answer: D
Solution:
- $ I=\frac{2Brv}{R/2}=\frac{4Brv}{R} $
Current in the top horizontal $ =2I=\frac{8Brv}{2R} $
BETA
