Electro Magnetic Induction And Alternating Currents Question 466
Question: An L-shaped conductor rod is moving in transverse magnetic field as . Potential difference between ends of the rod is maximum if the rod is moving with velocity
Options:
A) $ 4\hat{i}-6\hat{j},m/s $
B) $ -,4\hat{i}+6\hat{j},m/s $
C) $ 3\hat{i}+2\hat{j},m/s $
D) $ \sqrt{13}\hat{i},m/s $
Show Answer
Answer:
Correct Answer: C
Solution:
-
For maximum potential difference the velocity must be perpendicular to the line AB, and so
$ \vec{v}=v,\sin ,\theta \hat{i}+v,\cos \theta \hat{j} $
$ =v[ \frac{3}{\ell }\hat{i}+\frac{2}{\ell }\hat{j} ]=\frac{v}{\ell }[ 3\hat{i}+2\hat{j} ] $
BETA
