Electro Magnetic Induction And Alternating Currents Question 468
Question: A thin circular ring of area A is perpendicular to uniform magnetic field of induction B. A small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of circuit is R. When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is
Options:
A) $ \frac{BR}{A} $
B) $ \frac{AB}{R} $
C) ABR
D) $ B^{2},A/R^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ Q=\frac{\Delta \phi }{R}=\frac{{\phi_{2}}-{\phi_{1}}}{R}=\frac{BA-0}{R}=\frac{BA}{R} $
BETA
