Electro Magnetic Induction And Alternating Currents Question 469
A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mechanical power to move the conductor 1 m with a speed of $ 1m{{s}^{-1}} $ is
Options:
A) 0.25 m W
B) 6.25 W m
C) 0.625 W
1W
Show Answer
Answer:
Correct Answer: B
Solution:
$ P=Fv=BIlV=1.25\times {{10}^{-3}}\times 50\times 0.1\times 1 $
$ =6.25\times {{10}^{-3}}W=6.25mW $
BETA
