Electro Magnetic Induction And Alternating Currents Question 48
Question: A 220 V, 50 Hz ac source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series. What is the current in the circuit [MNR 1998; JIPMER 2001, 02]
Options:
A) 10 A
B) 5 A
C) 33.3 A
D) 3.33 A
Show Answer
Answer:
Correct Answer: D
Solution:
$ i=\frac{220}{\sqrt{{{(20)}^{2}}+{{(2\times \pi \times 50\times 0.2)}^{2}}}} $ $ =\frac{220}{66}=3.33,A $
BETA
