Electro Magnetic Induction And Alternating Currents Question 52
Question: In the circuit shown below, the ac source has voltage $ V=20\cos (\omega t) $ volts with $ \omega $ = 2000 rad/sec. the amplitude of the current will be nearest to [AMU (Engg.) 2000]
Options:
A) $ 2A $
B) $ 3.3A $
C) $ 2/\sqrt{5}A $
D) $ \sqrt{5}A $
Show Answer
Answer:
Correct Answer: A
Solution:
$ R=6+4=10,\Omega $
$ X_{L}=\omega L=2000\times 5\times {{10}^{-3}}=10,\Omega $
$ X_{C}=\frac{1}{\omega C}=\frac{1}{2000\times 50\times {{10}^{-6}}}=10,\Omega $
$ \therefore Z=\sqrt{R^{2}+{{(X_{L}-X_{C})}^{2}}}=10,\Omega $
Amplitude of current $ =i_{0}=\frac{V_{0}}{Z}=\frac{20}{10}=2A $
BETA
