Electro Magnetic Induction And Alternating Currents Question 522
Question: The current passing through a choke coil of 5 henry is decreasing at the rate of 2 ampere/sec. The e.m.f. developing across the coil is [CPMT 1982; MP PMT 1990; AIIMS 1997; MP PET 1999]
Options:
A) 10 V
B) ? 10 V
C) 2.5 V
D) ? 2.5 V
Show Answer
Answer:
Correct Answer: A
Solution:
Given $ \frac{di}{dt}=2A/sec.,\ L=5\ H $
$ \therefore \ e=L\frac{di}{dt}=5\times 2=10,V $
BETA
