Electro Magnetic Induction And Alternating Currents Question 547
Question: 5 cm long solenoid having 10 ohm resistance and 5 mH inductance is joined to a 10 volt battery. At steady state the current through the solenoid in ampere will be [MP PET 1995]
Options:
A) 5
B) 1
C) 2
D) Zero
Show Answer
Answer:
Correct Answer: B
Solution:
In steady state current passing through solenoid $ i=\frac{E}{R}=\frac{10}{10}=1\ A $
BETA
