Electro Magnetic Induction And Alternating Currents Question 557
Question: The mutual inductance between a primary and secondary circuits is 0.5 H. The resistances of the primary and the secondary circuits are 20 ohms and 5 ohms respectively. To generate a current of 0.4 A in the secondary, current in the primary must be changed at the rate of [MP PMT 1997]
Options:
A) 4.0 A/s
B) 16.0 A/s
C) 1.6 A/s
D) 8.0 A/s
Show Answer
Answer:
Correct Answer: A
Solution:
$ e_{2}=M\frac{di_{1}}{dt}\Rightarrow i_{2}R_{2}=M\frac{di_{1}}{dt}\Rightarrow 0.4\times 5=0.5\times \frac{di_{1}}{dt} $
$ \Rightarrow \frac{di_{1}}{dt}=4\ A/\sec . $
BETA
