Electro Magnetic Induction And Alternating Currents Question 68
A coil of 200 Ω resistance and 1.0 H inductance is connected to an ac source of frequency $ 200/2\pi ,Hz. $ Phase angle between potential and current will be [MP PMT 2003]
Options:
30o
90o
45o
0o
Show Answer
Answer:
Correct Answer: C
Solution:
$ \tan \varphi =\frac{X_{L}}{R}=\frac{2\pi \nu L}{R}=\frac{2\pi \times \frac{200}{2\pi }\times 1}{200}=1\Rightarrow \varphi =45^{o} $
BETA
