Electro Magnetic Induction And Alternating Currents Question 89
Question: The r.m.s. value of an ac of 50 Hz is 10 amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be [MP PET 1993; KCET 2003]
Options:
A) 2 ´ 10?2 sec and 14.14 amp
B) 1 ´ 10?2 sec and 7.07 amp
C) 5 ´ 10?3 sec and 7.07 amp
D) 5 ´ 10?3 sec and 14.14 amp
Show Answer
Answer:
Correct Answer: D
Solution:
Time taken by the current to reach the maximum value $ t=\frac{T}{4}=\frac{1}{4\nu }=\frac{1}{4\times 50}=5\times {{10}^{-3}}sec $ and $ i_{o}=i_{rms}\sqrt{2}=10\sqrt{2}=14.14 $ amp
BETA
