Electro Magnetic Induction And Alternating Currents Question 16
Question: An alternating voltage $ E=200\sqrt{2}\sin (100,t) $ is connected to a 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall be [NCERT 1984; MNR 1995; MP PET 1999; RPET 1999; UPSEAT 2000]
Options:
A) 10 mA
B) 20 mA
C) 40 mA
D) 80 mA
Show Answer
Answer:
Correct Answer: B
Solution:
Reading of ammeter $ =i_{rms}=\frac{V_{rms}}{X_{C}}=\frac{V_{0}\omega C}{\sqrt{2}} $ $ =\frac{200\sqrt{2}\times 100\times (1\times {{10}^{-6}})}{\sqrt{2}}=2\times {{10}^{-2}}A=20\ mA $
BETA
