Electro Magnetic Induction And Alternating Currents Question 179
Question: In the circuit shown, the symbols have their usual meanings. The cell has emf E. X is initially joined to V for a long time. Then, disjoined to Z The maximum charge on C at any later time will be
Options:
A) $ \frac{E}{R\sqrt{LC}} $
B) $ \frac{ER}{2\sqrt{LC}} $
C) $ \frac{E\sqrt{LC}}{2R} $
D) $ \frac{E\sqrt{LC}}{R} $
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Answer:
Correct Answer: D
Solution:
- Current in inductor $ =\frac{E}{R} $
$ \therefore $ its energy $ =\frac{1}{2}\frac{LE^{2}}{R^{2}} $ Same energy is later stored in capacitor $ \frac{Q^{2}}{2C}=\frac{1}{2}\frac{LE^{2}}{R^{2}}\Rightarrow Q=\sqrt{LC}\frac{E}{R} $
BETA
