Electro Magnetic Induction And Alternating Currents Question 188
Question: What is the amount of power delivered by the ac source in the circuit shown (in watts).
Options:
A) 500 watt
B) 1014 watt
C) 1514 watt
D) 2013 watt
Show Answer
Answer:
Correct Answer: C
Solution:
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$ {i _{1,rms}}=\frac{E _{rms}}{\sqrt{X _{C}^{2}+R _{1}^{2}}}=\frac{130}{13}=10A $
$ {i _{2,rms}}=\frac{E _{rms}}{\sqrt{X _{L}^{2}+R _{2}^{2}}}=13,A $
Power dissipated $ =i^{2} _{1,rms},R _{1}+i^{2} _{2,rms}R _{2}=10^{2}\times 5+13^{2}+6 $ = power delivered by battery $ =500+169\times 6=1514,watt $
BETA
