Electro Magnetic Induction And Alternating Currents Question 247
Question: A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is [MP PMT 1996]
Options:
A) 100 V, 16 A
B) 40 V, 40 A
C) 160 V, 10 A
D) 80 V, 20 A
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{V_{p}}{V_{s}}=\frac{N_{p}}{N_{s}}=\frac{500}{2500}=\frac{1}{5}\Rightarrow V_{p}=\frac{200}{5}=40\ V $
Also $ i_{p}V_{p}=i_{s}V_{s}\Rightarrow i_{p}=i_{s}\frac{V_{s}}{V_{p}}=8\times 5=40\ A $
BETA
