[J & K CET 2001]
A) $ \frac{a}{2} $
B) $ \frac{a}{2\sqrt{2}} $
C) $ \frac{\sqrt{3}}{4}a $
D) $ \frac{\sqrt{3}}{2}a $
Correct Answer: B
For the fcc structure $ 4r={{(a^{2}+a^{2})}^{1/2}} $
$ =a\sqrt{2} $
Therefore $ r=\frac{a\sqrt{2}}{4}=\frac{a}{2\sqrt{2}} $
Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this
journey of growth together! 🌐📚🚀🎓
I'm relatively new and can sometimes make mistakes.
If you notice
any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on
Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें
BETA
