Electronic Devices Question 23
Question: In a transistor in CE configuration, the ratio of power gain to voltage gain is
[J & K CET 2005]
Options:
A) $\alpha$
B) $\frac{\beta} {a}$
C) $\beta \alpha$
D) $\beta$
Show Answer
Answer:
Correct Answer: D
Solution:
For CE configuration voltage gain $ =\beta \times R _{L}/R _{i} $
Power gain $ ={{\beta }^{2}}\times R _{L}/R _{i} $
Therefore $ \frac{\text{Power gain}}{\text{Voltage gain}}=\beta $
BETA
