Electronic Devices Question 235
In the following common emitter configuration an NPN transistor with current gain β = 100 is used. The output voltage of the amplifier will be
[AIIMS 2003]
Options:
A) 10 mV
B) 0.1 V
C) 1.0 V
D) 10 V
Show Answer
Answer:
Correct Answer: C
Solution:
Voltage gain $ =\frac{\text{Output voltage}}{\text{Input voltage}} $
Therefore Vout = Vin x Voltage gain
Therefore Vout = Vin x Current gain x Resistance gain = Vin x b x $ \frac{R _{L}}{R _{BE}} $ = $ {{10}^{-3}}\times 100\times \frac{10}{1}=1V.$
BETA
