Electronic Devices Question 8
For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is 4.8 mA
[Haryana CET 1991]
Options:
A) 6 mA
B) 4.8 mA
C) 24 mA
D) 8 mA
Show Answer
Answer:
Correct Answer: C
Solution:
a = 0.8
$ \Rightarrow \beta =\frac{0.8}{(1-0.8)} $ =4.0
Also $ \beta =\frac{\Delta i _{c}}{\Delta i _{b}} $
$ \Rightarrow \Delta i _{c}=\beta \times \Delta i _{b} $ = 40 x 6 = 240mA.
BETA
