Electrostatics Question 1
Question: The capacity of a parallel plate condenser is $ 5\mu F $ . When a glass plate is placed between the plates of the conductor, its potential becomes $ 1/8th $ of the original value. The value of dielectric constant will be [MP PMT 1985]
Options:
1.6
5
8
40
Show Answer
Answer:
Correct Answer: C
Solution:
$ V’=\frac{V}{8} $
therefore $ \frac{V}{K}=\frac{V}{8} $
therefore K = 8
BETA
