Electrostatics Question 308
Question: The distance between $ {{H}^{+}} $ and $ C{{l}^{-}} $ ions in HCl molecule is 1.28 Å. What will be the potential due to this dipole at a distance of 12 Å on the axis of dipole [MP PMT 2002]
Options:
A) 0.13 V
B) 1.3 V
C) 13 V
D) 130 V
Show Answer
Answer:
Correct Answer: A
Solution:
$ V=9\times 10^{9}.\frac{p}{r^{2}} $
$ =9\times 10^{9}\times \frac{(1.6\times {{10}^{-19}})\times 1.28\times {{10}^{-10}}}{{{(12\times {{10}^{-10}})}^{2}}} $ = 0.13V
BETA
