Electrostatics Question 352
Question: Two plates are $ 2cm $ apart, a potential difference of$ 10\ volt $ is applied between them, the electric field between the plates is [MP PET 1994; DPMT 2002]
Options:
A) $ 20\ N/C $
B) $ 500N/C $
C) $ 5N/C $
D) $ 250\ N/C $
Show Answer
Answer:
Correct Answer: B
Solution:
$ E=\frac{V}{d}=\frac{10}{2\times {{10}^{-2}}}=500N/C $
BETA
