Electrostatics Question 401
Question: An electron enters between two horizontal plates separated by 2mm and having a potential difference of 1000V. The force on electron is [JIPMER 1999]
Options:
A) $ 8\times {{10}^{-12}} $ N
B) $ 8\times {{10}^{-14}} $ N
C) $ 8\times 10^{9} $ N
D) $ 8\times 10^{14} $ N
Show Answer
Answer:
Correct Answer: B
Solution:
Force on electron F = QE $ =Q( \frac{V}{d} ) $
therefore $ F=(1.6\times {{10}^{-19}})( \frac{1000}{2\times {{10}^{-3}}} )=8\times {{10}^{-14}}N $
BETA
