Electrostatics Question 425

The radius of a soap bubble whose potential is 16V is doubled. The new potential of the bubble will be 32V [Pb. PMT 2000]

Options:

2V

4V

8V

16V

Show Answer

Answer:

Correct Answer: C

Solution:

Potential $ V\propto \frac{1}{r}\Rightarrow V’=\frac{V}{2}=4V $

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