Electrostatics Question 446
Question: Kinetic energy of an electron accelerated in a potential difference of 100 V is [AFMC 1999; MP PMT 2002]
Options:
A) $ 1.6\times {{10}^{-17}} $ J
B) $ 1.6\times 10^{21} $ J
C) $ 1.6\times {{10}^{-29}} $ J
D) $ 1.6\times {{10}^{-34}} $ J
Show Answer
Answer:
Correct Answer: A
Solution:
By using $ KE=QV\Rightarrow KE=1.6\times 10^{-19}\times 100 $
$ =1.6\times 10^{17}J $
BETA
