Electrostatics Question 447
Question: A drop of $ {{10}^{-6}}kg $ water carries $ {{10}^{-6}}C $ charge. What electric field should be applied to balance its weight (assume $ g=10m/s^{2}) $ [MP PET 2002]
Options:
A) 10 V/m upward
B) 10 V/m downward
C) 0.1 V/m downward
D) 0.1 V/m upward
Show Answer
Answer:
Correct Answer: A
Solution:
By using therefore $ E=\frac{mg}{Q}=\frac{{{10}^{-6}}\times 10}{{{10}^{-6}}}=10V/m; $ upward because charge is positive.
BETA
