Electrostatics Question 455

Question: An $ \alpha $ -particle is accelerated through a potential difference of 200V. The increase in its kinetic energy is [UPSEAT 2002]

Options:

A) 100 eV

B) 200 eV

C) 400 eV

D) 800 eV

Show Answer

Answer:

Correct Answer: C

Solution:

$ KE=QV\Rightarrow KE=(2e)200V=400eV $



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