Electrostatics Question 134
Question: 64 drops of mercury each charged to a potential of $ 10V $ . They are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical) [MP PET 2003]
Options:
A) 160 V
B) 80 V
C) 10 V
D) 640 V
Show Answer
Answer:
Correct Answer: A
Solution:
$ V={{n}^{2/3}}v={{(64)}^{2/3}}\times 10=160volt $
BETA
