Electrostatics Question 488
Question: The potential at a distance R/2 from the centre of a conducting sphere of radius R will be [RPMT 2003]
Options:
A) 0
B) $ \frac{Q}{8\pi {\varepsilon _{0}}R} $
C) $ \frac{Q}{4\pi {\varepsilon _{0}}R} $
D) $ \frac{Q}{2\pi {\varepsilon _{0}}R} $
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Answer:
Correct Answer: C
Solution:
Potential inside the conducting sphere is same as that of surface i.e. $ \frac{Q}{4\pi {\varepsilon _{0}}R} $
BETA
