Electrostatics Question 535
In the circuit diagram, the resultant capacitance between P and Q is [MP PET/PMT 1988]
Options:
A) $ 47\mu F $
B) $ 3\mu F $
C) $ 60\mu F $
D) $ 10\mu F $
Show Answer
Answer:
Correct Answer: B
Solution:
The given circuit can be drawn as where $ C=(3+2)\mu F=5\mu F $
$ \frac{1}{C _{PQ}}=\frac{1}{5}+\frac{1}{20}+\frac{1}{12}=\frac{20}{60}=\frac{1}{3} $
therefore $ C _{PQ}=3\mu F $
BETA
