Electrostatics Question 538
Question: Two capacitances of capacity $ C _{1} $ and $ C _{2} $ are connected in series and potential difference $ V $ is applied across it. Then the potential difference across $ C _{1} $ will be [MP PMT 1985]
Options:
A) $ V\frac{C _{2}}{C _{1}} $
B) $ V\frac{C _{1}+C _{2}}{C _{1}} $
C) $ V\frac{C _{2}}{C _{1}+C _{2}} $
D) $ V\frac{C _{1}}{C _{1}+C _{2}} $
Show Answer
Answer:
Correct Answer: C
Solution:
Charge flowing $ =\frac{C _{1}C _{2}}{C _{1}+C _{2}}V $ . So potential difference across $ C _{1}=\frac{C _{1}C _{2}V}{C _{1}+C _{2}}\times \frac{1}{C _{1}} $
$ =\frac{C _{2}V}{C _{1}+C _{2}} $
BETA
