Electrostatics Question 222
Question: Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is [DCE 2004]
Options:
A) F / 8
B) F / 4
C) 4 F
D) F / 16
Show Answer
Answer:
Correct Answer: D
Solution:
$ F=k.\frac{Q^{2}}{r^{2}} $ . If Q is halved, r is doubled then $ F\to \frac{1}{16}\text{times} $
BETA
