Electrostatics Question 563
Question: $ 0.2F $ capacitor is charged to $ 600V $ by a battery. On removing the battery, it is connected with another parallel plate condenser of 1F. The potential decreases to [MNR 1978; MP PET 2002]
Options:
A) $ 100\ volts $
B) $ 120\ volts $
C) $ 300\ volts $
D) $ 600\ volts $
Show Answer
Answer:
Correct Answer: A
Solution:
By using charge conservation $ 0.2\times 600=(0.2+1)V $ therefore $ V=\frac{0.2\times 600}{1.2}=100V $
BETA
