Electrostatics Question 564
In the circuit, the potential difference across the 4.5 µF capacitor is
Options:
A) $ \frac{8}{3}\ volts $
B) 4 volts
C) 6 volts
D) 8 volts
Show Answer
Answer:
Correct Answer: D
Solution:
The given circuit can be redrawn as follows potential difference across 4.5 mF capacitor V$ =\frac{9}{( \frac{9}{2}+9 )}\times 12 $ = 4 V
BETA
