Electrostatics Question 564

In the circuit, the potential difference across the 4.5 µF capacitor is

Options:

A) $ \frac{8}{3}\ volts $

B) 4 volts

C) 6 volts

D) 8 volts

Show Answer

Answer:

Correct Answer: D

Solution:

The given circuit can be redrawn as follows potential difference across 4.5 mF capacitor V$ =\frac{9}{( \frac{9}{2}+9 )}\times 12 $ = 4 V



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