Electrostatics Question 145
Question: On increasing the plate separation of a charged condenser, the energy [Kerala PMT 2004]
Options:
A) Increases
B) Decreases
C) Remains unchanged
D) Becomes zero
Show Answer
Answer:
Correct Answer: A
Solution:
Energy $ U=\frac{1}{2}\frac{Q^{2}}{C} $ for a charged capacitor charge Q is constant and with the increase in separation C will decrease $ ( C\propto \frac{1}{d} ) $ , So overall U will increase.
BETA
