Electrostatics Question 590
Question: The equivalent capacitance between A and B is [RPMT 1999]
Options:
A) 2\ \mu F
B) 3\ \mu F
C) 5\ \mu F
D) 0.5\ \mu F
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{1}{C}=\frac{1}{2}+\frac{1}{1}+\frac{1}{2}=\frac{1+2+2}{2}=\frac{5}{2}=2.5 $ therefore $ C _{AB}=0.5\mu F $