Electrostatics Question 596
Question: In the circuit here, the steady state voltage across capacitor C is a fraction of the battery e.m.f. The fraction is decided by [AMU (Engg.) 2000]
Options:
A) $ {R _{\text{1}}} $ only
B) $ {R _{\text{1}}} $ and $ {R _{\text{2}}} $ only
C) $ R _{1} $ and $ R _{3} $ only
D) $ R _{1} $ ,$ R _{2} $ and $ R _{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
In steady state potential difference across capacitor
$ {V _{\text{2}}} $ = potential difference across resistance $ R _{2}=( \frac{R _{2}}{R _{1}+R _{2}} )V $
Hence ,$ {V _{\text{2}}} $
depends upon $ {R _{\text{2}}} $
and $ {R _{\text{1}}} $
BETA
