Electrostatics Question 611
Question: Two capacitors $ {C _{\text{1}}} $ and $ {C _{\text{2}}}=\text{ 2}{C _{\text{1}}} $ are connected in a circuit with a switch between them . Initially the switch is open and $ {C _{\text{1}}} $ holds charge Q. The switch is closed. At steady state, the charge on each capacitor will be [Orissa JEE 2002]
Options:
A) $ Q,2Q $
B) $ Q/3,2Q/3 $
C) $ 3Q/2,3Q $
D) $ 2Q/3,4Q/3 $
Show Answer
Answer:
Correct Answer: B
Solution:
In steady state charge on C1 is $ Q _{1}=( \frac{C _{1}}{C _{1}+C _{2}} )\times Q=\frac{Q}{3} $ and charge on C2 is $ Q _{2}=( \frac{C _{2}}{C _{1}+C _{2}} ).Q=\frac{2}{3}Q $
BETA
