Electrostatics Question 624
Question: A capacitor of capacity $ C _{1} $ is charged upto V volt and then connected to an uncharged capacitor of capacity $ C _{2} $ . Then final potential difference across each will be [MP PET 2000; CBSE PMT 2002; MP PET 2003]
Options:
A) $ \frac{C _{2}V}{C _{1}+C _{2}} $
B) $ ( 1+\frac{C _{2}}{C _{1}} )V $
C) $ \frac{C _{1}V}{C _{1}+C _{2}} $
D) $ ( 1-\frac{C _{2}}{C _{1}} )V $
Show Answer
Answer:
Correct Answer: C
Solution:
Common potential $ {V}’=\frac{C _{1}V+C _{2}\times 0}{C _{1}+C _{2}}=\frac{C _{1}}{C _{1}+C _{2}}.V $
BETA
