Electrostatics Question 629
Question: The charge on 4 mF capacitor in the given circuit is …. in mC [Kerala PMT 2004]
Options:
12
24
36
32
Show Answer
Answer:
Correct Answer: B
Solution:
Equivalent capacity between A and B $ =\frac{6\times 4}{10}=2.4\mu F $ .
Hence charge across 4mF (Since in series combination charge remains constant) or $ \text{6}\mu F=\text{ 2}.\text{4}\times \text{1}0^1=\text{ 24}\mu C $
BETA
