Electrostatics Question 633
Question: Three capacitors of capacitance 1 mF, 2 mF and 3 mF are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 mF capacitor is [DCE 2003]
Options:
2 V
4 V
1 V
6 V
Show Answer
Answer:
Correct Answer: D
Solution:
Equivalent capacitance $ \frac{1}{C {eq}}=\frac{1}{C{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}} $
therefore $ C _{eq}=\frac{6}{11}\mu F $
Charge supplied from battery $ Q=\frac{6}{11}\times 11=6\mu C $
Hence potential difference across 1µF capacitor $ =\frac{6}{1}=6V $
BETA
