Electrostatics Question 655
Question: For section AB of a circuit ,$ C _{1}=1\mu F $ , $ C _{2}=2\mu F $ , $ E=10V $ , and the potential difference $ V _{A}-V _{B}=10V $ . Charge on capacitor $ C _{1} $ is
Options:
A) $ 0\mu C $
B) $ 20/3\mu C $
C) $ 40/3\mu C $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ V _{A}-\frac{q}{C _{1}}-E-\frac{q}{C _{2}}=V _{B} $ or $ V _{A}-V _{B}-E=q( \frac{1}{C _{1}}+\frac{1}{C _{2}} ) $ or $ q=-\frac{40}{3}\mu C $
BETA
