Electrostatics Question 673
The electric flux from a cube of edge $ l $ is $ \phi $. If an edge of the cube is made $ 2l $ and the charge enclosed is halved, its value will be
Options:
A) $ 4\phi $
B) $ 2\phi $
C) $ \phi /2 $
D) $ \phi $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ \phi =\frac{q}{{\varepsilon _{0}}} $ (independent of dimensions) New flux, $ \phi ‘=\frac{\phi }{2} $
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