Electrostatics Question 690
Question: In fig., two equal positive point charges $ q _{1}=q _{2}=2.0\mu C $ interact with a third point charge $ Q=4.0\mu C $ . The magnitude, as well as direction, of the net force on Q is
Options:
A) 0.23 N in the +x-direction
B) 0.46 N in the +x-direction
C) 0.23 N in the +x-direction
D) 0.46 N in the +x-direction
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ F _{net}=2|F _{31}|cos\alpha $
$ =2\times \frac{1}{4\pi {\varepsilon _{0}}}\times \frac{2\times 4\times {{10}^{-12}}}{{{( 0.5 )}^{2}}}\times \frac{4}{5}=0.46N $
BETA
